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Interpolation Calculator Between Two Points

Interpolation Formula:

\[ y = y1 + \frac{(y2 - y1)}{(x2 - x1)} \times (x - x1) \]

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1. What Is Interpolation Between Two Points?

Interpolation between two points is a mathematical method used to estimate an unknown value that lies between two known data points. It assumes a linear relationship between the points and calculates the intermediate value based on this assumption.

2. How Does The Calculator Work?

The calculator uses the linear interpolation formula:

\[ y = y1 + \frac{(y2 - y1)}{(x2 - x1)} \times (x - x1) \]

Where:

Explanation: This formula calculates the slope between the two known points and applies it to find the y-value at the given x-position between them.

3. Importance Of Interpolation Calculation

Details: Interpolation is essential in various fields including mathematics, engineering, data analysis, and computer graphics where estimating values between known data points is necessary for predictions, animations, and scientific computations.

4. Using The Calculator

Tips: Enter the coordinates of two known points (x1,y1) and (x2,y2), then provide the x-value where you want to interpolate. Ensure x2 is not equal to x1 to avoid division by zero errors.

5. Frequently Asked Questions (FAQ)

Q1: What is the difference between interpolation and extrapolation?
A: Interpolation estimates values within the range of known data points, while extrapolation predicts values outside this range.

Q2: When is linear interpolation appropriate?
A: Linear interpolation works best when the relationship between data points is approximately linear or when you need a simple estimation between closely spaced points.

Q3: What are the limitations of linear interpolation?
A: It assumes a straight-line relationship between points, which may not accurately represent more complex nonlinear relationships in the data.

Q4: Can I use this for 3D interpolation?
A: No, this calculator is designed for 2D linear interpolation between two points. 3D interpolation requires more complex methods.

Q5: What if my x-value is outside the range of x1 and x2?
A: The formula will still calculate a result, but this becomes extrapolation rather than interpolation, which may be less accurate.

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